3x+9^2=2x+2(2x+2+27)

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Solution for 3x+9^2=2x+2(2x+2+27) equation: 



3x+9^2=2x+2(2x+2+27)

We move all terms to the left:

3x+9^2-(2x+2(2x+2+27))=0

We add all the numbers together, and all the variables

3x-(2x+2(2x+29))+9^2=0

We add all the numbers together, and all the variables

3x-(2x+2(2x+29))+81=0



We calculate terms in parentheses: -(2x+2(2x+29)), so:

2x+2(2x+29)

We multiply parentheses

2x+4x+58

We add all the numbers together, and all the variables

6x+58

Back to the equation:

-(6x+58)



We get rid of parentheses

3x-6x-58+81=0

We add all the numbers together, and all the variables

-3x+23=0

We move all terms containing x to the left, all other terms to the right

-3x=-23

x=-23/-3

x=7+2/3

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